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The treatment of benzene with isobutene in the presence of sulphuric acid gives

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Important Points to Remember in Chapter 10 - Haloalkanes and Haloarenes from Embibe Experts Achieve CUET (UG) Chemistry Practice Book Solutions

1. Classification of Haloalkanes and Haloarenes:

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2. Preparation of Haloalkanes:

(i) From Alcohols:

R-OH+HClZnCl2R-Cl+H2O  

R-OH+NaBr+H2SO4R-Br+NaHSO4+H2O

3R-OH+PX33R-X+H3PO3(X=Cl,Br)

R-OH+PClsR-Cl+POCl3+HCl

R-OHx2=Br2,I2red P/X2R-X

R-OH+SOCl2R-Cl+SO2+HCl

(ii) From alkanes by free radical halogenation :

CH3CH2CH2CH3or heatCl2/UV lightCH3CH2CH2CH2Cl+CH3CH2CHClCH3

(iii) From Alkenes by addition of hydrogen halides -

CH3CH=CH2+H-ICH3CH2CH2IMinor+CH3CHICH3Major

(iv) From Alkenes by addition of Halogens

C2H4+Br2CCl4BrCH2-CH2Br

(v) By Halogen exchange method:

(a) Finkelstein reaction:
CH3CH2Br+Nalheat AcetoneCH3CH2I+NaBr

(b) Swart's reaction:
CH3Br+AgFCH3 F+AgBr

3. Preparation of Haloarenes:

(i) From hydrocarbons by electrophilic substitution :

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(ii) From amines by Sandmeyer’s reaction :

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4. Nucleophilic substitution reactions :

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(i) The reactivity of alkyl halides towards SN2 mechanism is: methyl > 1° > 2° > 3°.

(ii) The SN1 mechanism occurs through the formation of carbocation. The order of reactivity is: 3° > 2° > 1° > methyl

5. Reaction with metals (Wurtz reaction):

 C2H5Br+2Na+C2H5BrDry etherCH3CH2CH2CH3+2NaBr

6. Reduction: C2H5BrZn/Cu couple or Sn/HClH2,Ni or HI, red P or C2H6+HBr

7. Elimination reactions: C2H5Bralc. KOHCH2=CH2alkene+HBr

8. Reaction of Haloarenes:

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