To verify Ohm’s law, a student connects the voltmeter across the battery as shown in the figure. The measured voltage is plotted as a function of the current, and the following graph is obtained:

If ${\mathrm{V}}_{\mathrm{o}}$ is almost zero, identify the correct statement:

The galvanometer deflection, when key $K_1$ is closed but $K_2$ is open, equals ${\theta }_0$ (see figure). On closing $K_2$ also and adjusting $R_2$ to $5\Omega ,$ the deflection in galvanometer becomes $\frac{{\theta }_0}{5}.$ The resistance of the galvanometer is, then, given by [Neglect the internal resistance of battery]:

In a meter bridge, the wire of length $1 m$ has a non-uniform cross-section such that, the variation $\frac{dR}{dl}$ of its resistance $R$ with length $l$ is $\frac{dR}{dl}\propto \frac{1}{\sqrt{l}}.$ Two equal resistances are connected as shown in the figure. The galvanometer has zero deflection when the jockey is at point $P.$ What is the length $AP?$

Two batteries with e.m.f. $12 \mathrm{V}$ and $13 \mathrm{V}$ are connected in parallel across a load resistor of $10 \mathrm{\Omega }$. The internal resistance of the two batteries are $1 \mathrm{\Omega }$ and $2 \mathrm{\Omega }$ respectively. The voltage across the load lies between,