MEDIUM
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Two liquids A and B form an ideal solution. At 300 K the vapour pressure of a solution of 1 mole of A and x moles of B is 550 mm of Hg. If the vapour pressures of pure A and B are 400 mm of Hg nd 600 mm of Hg respectively, then x is -

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Important Questions on Solutions

MEDIUM
A solution contains 5 moles of X and 5 moles of Y, and has a normal boiling point of 90°C. The vapor pressure of pure X is 300 mm Hg. What is the vapor pressure of pure Y at this temperature?
HARD
Which of the following statements about the composition of the vapour over an ideal 1 : 1 molar mixture of benzene and toluene is correct? Assume that the temperature is constant at 25oC . (Given vapour pressure data at 25oC , benzene = 12.8 kPa, toluene = 3.85 kPa)
HARD

Benzene and toluene form an ideal solution over the entire range of composition. The vapour pressure of pure benzene and toluene at T K are 50 mmHg and 40 mmHg, respectively. What is the mole fraction of toluene in vapour phase when 117 g of benzene is mixed with 46 g of toluene?

(Molar mass of benzene and toluene are 78 and 92 g mol-1, respectively)

EASY
On mixing 20 mL of acetone with 60 mL of chloroform, the total volume of the solution is
HARD
Liquids A and B form an ideal solution in the entire composition range. At 350K, the vapour pressure of pure A and pure B are 7×103Pa and 12×103Pa , respectively. The composition of the vapour in equilibrium with a solution containing 40 mole percent of A at this temperature is:
EASY
A mixture of toluene and benzene forms a nearly ideal solution. Assume PB° and PT° to be the vapor pressures of pure benzene and toluene, respectively. The slope of the line obtained by plotting the total vapor pressure to the mole fraction of benzene is:
MEDIUM
How many grams of glucose are required to prepare an aqueous solution of glucose having a vapor pressure of 23.324 mm Hg at 25°C in 100 g of water? The vapour pressure of pure water at 25°C is 23.8 mm Hg.
MEDIUM
A mixture of toluene and benzene boils at 100oC . Assuming ideal behaviour, the mole fraction of toluene in the mixture is closest to [Vapour pressures of pure toluene and pure benzene at 100oC are 0.742 and 1.800 bar respectively. 1 atm =1.013  bar]
EASY
9 gram anhydrous oxalic acid (mol. Wt. = 90) was dissolved in 9.9 moles of water. If vapour pressure of pure water is P1o the vapour pressure of solution is
MEDIUM
An open beaker of water in equilibrium with water vapour is in a sealed container. When a few grams of glucose are added to the beaker of water, the rate at which water molecules :
EASY
The vapour pressure of pure liquids A and B are 450 and 700 mm of Hg at 350 K respectively. If the total vapour pressure of the mixture is 600 mm of Hg, the composition of the mixture in the solution is
MEDIUM
The vapour pressures of pure liquids A and Bare 400 and 600 mm Hg respectively at 298 K. On mixing the two liquids, the sum of their volumes is equal to the volume of the final mixture. The mole fraction of liquid B is 0.5 in the mixture. The vapour pressure of the final solution, the mole fractions of components A and B in the vapour phase, respectively are 
EASY

The correct option for the value of vapour pressure of a solution at 45ºC with benzene to octane in molar ratio 3 : 2 is:

[At 45°C vapour pressure of benzene is 280 mm Hg and that of octane is 420 mm Hg. Assume Ideal gas]

HARD
The plot of total vapour pressure as a function of mole fraction of the components of an ideal solution formed by mixing liquids X and Y is
HARD
Liquids A and B form ideal solution over the entire range of composition. At temperature T, equimolar binary solution of liquids A and B has vapour pressure 45 Torr . At the same temperature, a new solution of A and B having mole fractions xA and xB, respectively, has vapour pressure of 22.5 Torr. The value of xAxB, in the new solution is ____.

(Given that the vapour pressure of pure liquid A is 20 Torr at temperature T)
MEDIUM
At 300 K, the vapour pressure of a solution containing 1 mole of n -hexane and 3 moles of n -heptane is 550 mm of Hg. At the same temperature, if one more mole of n -heptane is added to this solution, the vapour pressure of the solution increases by 10 mm of Hg. What is the vapour pressure in mmHg of n - heptane in its pure state______?
MEDIUM
A solution is prepared by mixing 8.5 g of CH2Cl2 and 11.95 g of CHCl3 . If vapour pressure of CH2Cl2 and CHCl3 at 298K are 415 and 200 mm Hg respectively, the mole fraction of CHCl3 in vapour form is: Molar mass of Cl=35.5 g mol-1
MEDIUM
38.4 g of unknown substance (molar mass 384 g mol-1) and 116 g of acetone is used to prepare a solution at 313 K. If vapour pressure of pure acetone (molar mass 58 g mol-1) is 0.842 atmosphere, what is the vapour pressure of solution ?
MEDIUM
Liquid M and liquid N form an ideal solution. The vapour pressures of pure liquids M and N are 450 and 700 mmHg, respectively, at the same temperature. Then correct statements is:
( xM=Mole fraction of 'M' in solution;
xN=Mole fraction of 'N'in solution;
yM=Mole fraction of 'M' in vapour phase;
yN=Mole fraction of 'N' in vapour phase; )
MEDIUM
A solution at 20oC is composed of 1.5 mol of benzene and 3.5 mol of toluene. If the vapour pressure of pure benzene and pure toluene at this temperature are 74.7 torr and 22.3 torr respectively, then the total vapour pressure of the solution and the benzene mole fraction in equilibrium with it will be, respectively: