Two vessels $A$ and $B$ of different shape have the same base area and are filled with water upto the same height $h$. The force exerted by water on the base is $F_A$ for vessel $A$ and $F_B$ for vessel $B$. The respective weight of the vessels are $W_A$ and $W_B$. Then

 

A uniformly tapering vessel shown in figure is filled with a liquid of density $1000\mathrm{kg}{\mathrm{m}}^{-3}$. The force that acts on the base of the vessel due to the liquid is (Take $g=10{\mathrm{ms}}^{-2}$)

A slender homogeneous rod of length $2\mathrm{L}$ floats partly immersed in water being supported by a string fastened to one of its end. The specific gravity of the rod is $0.75$. The length of rod that extends out of water is

A body having volume $V$ is floating, fully submerged in a liquid of density $\rho$. If the container starts moving upward with constant acceleration $\frac{g}{3}$ then the buoyant force acting on the body will become

If container is accelerated towards right with acceleration $a=g$. Find pressure at $A$.