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What are the advantages of polar orbiting satellites?
 

Important Questions on Gravitation

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The weight suspended from a spring oscillates up and down. The acceleration of weight will be zero at
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A geostationary satellite orbits around the earth in a circular orbit of radius 36000 km. Then, the time period of a sky satellite orbiting a few 100 km above the earth's surface R=64000 km will approximately be
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A satellite is launched to a distance r from the centre of the earth to have a circular orbit around the earth. Its orbital velocity to maintain this orbit is (mass of the earth as ME)
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A person jumps from the 5th  storey of a building with load on his head. The weight experienced by him before reaching the earth will be
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A test particle is moving in a circular orbit in the gravitational field produced by a mass density ρr=Kr2. Identify the current relation between the radius R of the particle’s orbit and its period T:
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Two satellites A and B are revolving with critical velocities vA and vB around the earth, in circular orbits of radii R and 2R respectively. The ratio vAvB is
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A planet is moving in a circular orbit. It completes 2 revolutions in 360 days. What is its angular frequency?
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A geostationary satellite is orbiting around an arbitrary planet P at a height of 11R above the surface of P, R being the radius of P. The time period of another satellite in hours at a height of 2R from the surface of P is ________ has the time period of 24 hours.
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A spaceship orbits around a planet at a height of 20 km from its surface. Assuming that only gravitational field of the planet acts on the spaceship, what will be the number of complete revolutions made by the spaceship in 24 hours around the planet?
[Given: Mass of planet  =8×1022 kg ,
Radius of planet =2×106 m,
Gravitational constant  G=6.67×10-11 Nm2/kg2 ]
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If the distance between sun and earth is d, then the angular momentum of earth around the sun is proportional to
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Two satellites A and B of masses 200 kg and 400 kg are revolving round the earth at height of 600 km and 1600 km respectively. If TA and TB are the time periods of A and B respectively then the value of TB-TA :

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[ Given : radius of earth =6400 km, mass of earth =6×1024 kg ]

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The relative uncertainty in the period of a satellite orbiting around the earth is 10-2 . If the relative uncertainty in the radius of the orbit is negligible, the relative uncertainty in the mass of the earth is:
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Consider two satellites S1 and S2 with periods of revolution 1hr and 8hr respectively revolving around a planet in circular orbits. The ratio of angular velocity of satellite S1 to the angular velocity of satellite S2 is:
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Earth revolves round the sun in a circular orbit of radius R. The angular momentum of the revolving earth is directly proportional to
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A geostationary satellite is orbiting the earth at a height 6R above the surface of the earth, where R is the radius of the earth. The time period of another satellite at a height 2.5R from the surface of the earth is
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The planet Mars has two moons, if one of them has a period 7 hours, 30 minutes and an orbital radius of 9.0×103 km. Find the mass of Mars.
Given 4π2G=6×1011 N-1 m-2 kg2
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The time period of an earth satellite in circular orbit is independent of
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A body is moving in a low circular orbit about a planet of mass M and radius R. The radius of the orbit can be taken to be R itself. Then the ratio of the speed of this body in the orbit to the escape velocity from the planet is: 
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A satellite is revolving in a circular orbit at a height h from the earth's surface (radius of earth R; h << R ). The minimum increase in its orbital velocity required, so that the satellite could escape from the earth's gravitational field, is close to (Neglect the effect of atmosphere.)
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The minimum number of geostationary satellites required for uninterrupted global coverage is