What happens when benzyl chloride is treated with ammonia followed by the reaction with chloromethane.

What are $\mathrm{P}$ and $\mathrm{Q}$ in the following reactions?

Starting from propanoic acid, the following reactions were carried out 
Propanoic acid $\stackrel{{\mathrm{SOCl}}_2}{⟶}\mathrm{X}\stackrel{{\mathrm{NH}}_3}{⟶}\mathrm{Y}⟶{\mathrm{Z}}_2+\mathrm{KOH}\to \mathrm{Z}$

What is the compound $\mathrm{Z}$?

In the reaction, 

${\mathrm{CH}}_3·{\mathrm{CH}}_2·\mathrm{Cl}\stackrel{\mathrm{KCN}}{⟶}\left(\mathrm{A}\right)\stackrel{{\mathrm{LiAlH}}_4}{⟶}\left(\mathrm{P}\right)$ end product $\left(\mathrm{P}\right)$ is

Identify $\text{'}\mathrm{A}\text{'}$ in the following reaction $\mathrm{R}-{\mathrm{NO}}_2\underset{\mathrm{neutral} \mathrm{medium} }{\overset{\mathrm{Zn}/{\mathrm{NH}}_4\mathrm{Cl}}{\to }}\mathrm{A}+{\mathrm{H}}_2\mathrm{O}$