Frustum is a Latin word. Its meaning is piece cut off . Take some clay and form a cone. Cut it with a knife parallel to its base. Remove the smaller cone. The left out portion is called a frustum of a cone.

Match the following: Volume of a cone 2 π r h Volume of a frustum 3 π r 2 Total surface area of a cone 2 3 π r 3 Total surface area of a hemisphere l b h Volume of a cuboid π r l Lateral surface area of cylinder 2 π r r + h Surface area of a sphere 1 3 π r 2 h Volume of hemisphere π r r + l Curved surface area of cone 4 π r 2 Total surface area of a cylinder 1 3 π h R 2 + r 2 + R r

Volume of a cone 1 3 π r 2 h Volume of a frustum 1 3 π h R 2 + r 2 + R r Total surface area of a cone π r r + l Total surface area of a hemisphere 3 π r 2 Volume of a cuboid l b h Lateral surface area of a cylinder 2 π r h Surface area of a sphere 4 π r 2 Volume of a hemisphere 2 3 π r 3 Curved surface area of a cone πrl Total surface area of a cylinder 2 π r r + h

E M B I B E

DINESH LAB MANUAL IN MATHEMATICS CLASS X>Chapter 13 - Surface Areas and Volumes>ACTIVITY (Frustum)>Q 1

EASY

10th CBSE

IMPORTANT

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What is a Frustum?

Important Questions on Surface Areas and Volumes

MEDIUM

10th CBSE

IMPORTANT

DINESH LAB MANUAL IN MATHEMATICS CLASS X>Chapter 13 - Surface Areas and Volumes>WORKSHEET (Self Assessment)>Q 1

Match the following:

Volume of a cone	$2 π r h$
Volume of a frustum	$3 π r^{2}$
Total surface area of a cone	$\frac{2}{3} π r^{3}$
Total surface area of a hemisphere	$l b h$
Volume of a cuboid	$π r l$
Lateral surface area of cylinder	$2 π r (r + h)$
Surface area of a sphere	$\frac{1}{3} π r^{2} h$
Volume of hemisphere	$π r (r + l)$
Curved surface area of cone	$4 π r^{2}$
Total surface area of a cylinder	$\frac{1}{3} π h (R^{2} + r^{2} + R r)$