EASY
Earn 100

What is abnormal molecular mass? Discuss its being in molecular association/dissociation.

Important Questions on Solutions

MEDIUM
Acetic acid dimerises when dissolved in benzene. As a result boiling point of the solution rises by 0.36°C, when 100 g of benzene is mixed with X g of acetic acid. In this solution, if experimentally measured molecular weight of acetic acid is 117.8 and molar elevation constant of benzene is 2.57 K kg mol-1, what is the weight % and degree of dissociation (in %) of acetic acid in benzene?
MEDIUM
If 8 g of a non-electrolyte solute is dissolved in 114 g of n-octane to reduce its vapour pressure to 80%, the molar mass (in g mol-1) of the solute is [Given that molar mass of n-octane is 114 g mol-1]
EASY
An aqueous solution containing 1.0 g of urea boils at 100.25°C. The aqueous solution containing 3.0 g of glucose in the same volume will boil at:
MEDIUM
The vapour pressure of acetone at 20oC is 185 torr. When 1.2 g of a non-volatile substance was dissolved in 100 g of acetone at 20oC , its vapour pressure was 183 torr. The molar mass (g mol-1) of the substance is:
EASY
The correct relation between the elevation in boiling point and the molar mass of a solute is: ( W 1 and W 2 are respectively weight of solvent & solute)
MEDIUM
Two solutions A and B are prepared by dissolving 1 g of non-volatile solutes X and Y. respectively in 1 kg of water. The ratio of depression in freezing points for A and B is found to be 1:4. The ratio of molar masses of X and Y is
MEDIUM
Solution of 'A' containing 3·42 g of it in 100 cm3 of water is found to be isotonic with a 6.84% (W/v) solution of sucrose, what is the molar mass of ''A'? (at. wt; C=12,H=1,0=16)
MEDIUM
Give reasons for the following:
Measurement of osmotic pressure method is preferred for the determination of molar masses of macromolecules such as proteins and polymers.
MEDIUM
A non-volatile solute, A'' tetramerises in water to the extent of 80%2.5 g of A'' in 100 g of water, lowers the freezing point by 0.3°C. the molar mass of A in g mol-1 is (Kf for water =1.86 K kg mol-1)
MEDIUM
When the same amount of the solute 'P' and 'Q' are separately dissolved in 500g water, the Δ Tf values are 0.15K and 0.30K respectively. If the molecular weight of P'' is 80g mol-1, then the molecular weight of Q'' is
HARD
Molecules of benzoic acid C6H5COOH dimerise in 30g of benzene. ' w ' g of benzoic acid shows a depression in freezing point equal to K. If the percentage association of the acid to form dimer in the solution is 80, then w is: ( Given that Kf=5 K kg mol-1, molar mass of benzoic acid =122 gmol-1)
MEDIUM

Determination of the molar mass of acetic acid in benzene using freezing point depression is affected by:

MEDIUM
The boiling point of benzene is 353.23 K. When 1.80 g of non-volatile solute was dissolved in 90 g of benzene, the boiling point of is raised to 354.11 K. Calculate the molar mass of the solute. (Kb for benzene is 2.53 K Kg mol-1)
EASY
The osmotic pressure of 1L of an aqueous solution containing 0.97 g of an organic compound is 0.08 atm at 300 K. The molar mass of the organic compound (in g mol-1) is [Gas constant, R=0.08 L atmK-1mol-1]
EASY
Give reasons for the following:
Elevation of boiling point of 1 M KCl solution is nearly double than that of 1 M sugar solution.
MEDIUM
Visha took two aqueous solutions — one containing 7·5 g of urea (Molar mass = 60 g/mol) and the other containing 42·75 g of substance Z in
100 g of water, respectively. It was observed that both the solutions froze at the same temperature. Calculate the molar mass of Z.
HARD
Calculate the mass of ascorbic acid Molar Mass = 176 g mol-1 to be dissolved in 75 g of acetic acid, to lower its freezing point by 1.5°C. Kf = 3.9 K kg mol-1
MEDIUM
58.5 g of NaCl and 180 g of glucose were separately dissolved in 1000 mL of water. Identify the correct statement regarding the elevation of boiling point (b.pt.) of the resulting solutions.
EASY
In 108 g of water, 18 g of a non-volatile compound is dissolved. At 100o C the vapor pressure of the solution is 750 mm Hg. Assuming that the compound does not undergo association or dissociation, the molar mass of the compound in g mol-1 is
MEDIUM
The freezing point of a 4% aqueous solution of X is equal to the freezing point of a 12% aqueous solution of Y. If the molecular weight of X is A, then the molecular weight of Y will be