Match the corresponding entries of column 1 with column 2. [Where m is the magnification produced by the mirror] Column 1 Column 2 (A) m = - 2 (a) Convex mirror (B) m = - 1 2 (b) Concave mirror (C) m = + 2 (c) Real image (D) m = + 1 2 (d) Virtual image

A → b and c; B → b and c; C → b and d; D → a and d

A → a and c; B → a and d; C → a and b; D → c and d

A → a and d; B → b and c; C → b and d; D → b and c

A → c and d; B → b and d; C → b and c; D → a and d

EASY

Earn 100

What is linear magnification?

Important Questions on Reflection of Light

HARD

Physics>Optics>Reflection of Light>Mirror Equation

A candle placed

25 cm

from a lens forms an image on the screen placed

75 cm

on the other side of the lens. The focal length and type of the lens should be

EASY

Physics>Optics>Reflection of Light>Mirror Equation

An object of height

2.5 cm

is placed perpendicularly on the principal axis of a concave mirror of focal length

f

at a distance of

\frac{3}{4} f

What will be the nature of the image of the object and its height

MEDIUM

Physics>Optics>Reflection of Light>Mirror Equation

A point object is moving uniformly towards the pole of a concave mirror of focal length $25 cm$ along its axis as shown below. The speed of the object is $1 {ms}^{- 1}$ . At $t = 0$ , the distance of the object from the mirror is $50 cm$ . The average velocity of the image formed by the mirror between time $t = 0$ and $t = 0.25 s$ is:

Question Image

EASY

Physics>Optics>Reflection of Light>Mirror Equation

An object is placed at a distance of

20 cm

from the pole of a concave mirror of focal length

10 cm

. The distance of the image formed is

MEDIUM

Physics>Optics>Reflection of Light>Mirror Equation

Match the corresponding entries of column 1 with column 2. [Where m is the magnification produced by the mirror]

	Column 1		Column 2
(A)	$m = - 2$	(a)	Convex mirror
(B)	$m = - \frac{1}{2}$	(b)	Concave mirror
(C)	$m = + 2$	(c)	Real image
(D)	$m = + \frac{1}{2}$	(d)	Virtual image

EASY

Physics>Optics>Reflection of Light>Mirror Equation

A concave mirror of focal length

15 cm

, forms an image having twice the linear dimensions of the object. The position of the object, when the image is virtual, will be

MEDIUM

Physics>Optics>Reflection of Light>Mirror Equation

To find the focal length of a convex mirror, a student records the following data:

Object pin	Convex Lens	Convex Mirror	Image Pin
22.2 cm	32.2 cm	45.8 cm	71.2 cm

The focal length of the convex lens is

f_{1}

and that of mirror is

f_{2}

. Then taking index correction to be negligibly small,

f_{1}

and

f_{2}

are close to:

EASY

Physics>Optics>Reflection of Light>Mirror Equation

In an optics experiments, with the position of the object fixed, a student varies the position of a convex lens and for each position, the screen is adjusted to get a clear image of the object. A graph between the object distance

u

and the image distance

v,

from the lens, is plotted using the same scale for the two axes. A straight line passing through the origin and making an angle of

45 °

with the

x

-axis meets the experimental curve at

P .

The coordinates of

P

will be

MEDIUM

Physics>Optics>Reflection of Light>Mirror Equation

A thin rod of

5 c m

length is kept along the axis of a concave mirror of

10 c m

focal length such that its image is real and magnified and one end touches the rod. Its magnification will be -

MEDIUM

Physics>Optics>Reflection of Light>Mirror Equation

An object of length 1 cm is placed at a distance of 15 cm from a concave mirror of focal length 10 cm. The nature and size of the image are

EASY

Physics>Optics>Reflection of Light>Mirror Equation

An object is placed in front of a convex mirror at a distance of 50 cm. A plane mirror is introduced covering the lower half of the convex mirror. If the distance between the object and the plane mirror is 30 cm, it is found that there is no gap between the images formed by the two mirrors. The radius of the convex mirror is:

EASY

Physics>Optics>Reflection of Light>Mirror Equation

An object is placed in front of a convex mirror of focal length

f .

Find the maximum and minimum distance of two object from the mirror such that the image is real and magnified.

MEDIUM

Physics>Optics>Reflection of Light>Mirror Equation

A point object is placed at a distance of

10 cm

and its real image is formed at a distance of

20 cm

from a concave mirror. If the object is moved by

0.1 cm

towards the mirror, the image will shift by about

HARD

Physics>Optics>Reflection of Light>Mirror Equation

A large temple has a depression in one wall. On the floor plan, it appears as an indentation having a spherical shape of radius

2.50 m

. A worshipper stands on the centreline of the depression,

2.00 m

out from its deepest point, and whispers a prayer. Where is the sound concentrated after reflection from the black wall of the depression?

EASY

Physics>Optics>Reflection of Light>Mirror Equation

Assertion: The formula connecting u, v and f for a spherical mirror is valid only for mirrors whose sizes are very small compared to their radii of curvature.

Reason: Laws of reflection are strictly valid for plane surfaces, but not for large spherical surfaces.

MEDIUM

Physics>Optics>Reflection of Light>Mirror Equation

A student performed the experiment of determination of the focal length of a concave mirror by

u - v

method using an optical bench of length

1.5 m

. The focal length of the mirror used is

24 cm

. The maximum error in the location of the image can be

0.2 cm

. The

5

sets of

(u, v)

values recorded by the student (in

cm

) are :

(45, 56), (48, 48), (60, 40), (66, 33), (78, 39)

. The data set (s) that cannot come from experiment and is (are) incorrectly recorded, is are

EASY

Physics>Optics>Reflection of Light>Mirror Equation

Assertion: For observing traffic at our back, we prefer to use a convex mirror.

Reason: A convex mirror has a much larger field of view than a plane mirror or a concave mirror.

EASY

Physics>Optics>Reflection of Light>Mirror Equation

An infinitely long rod lies along the axis of concave mirror of focal length

f .

The near end of the rod is at a distance

x > f

from the mirror. Then the length of the image of the rod is

EASY

Physics>Optics>Reflection of Light>Mirror Equation

Assertion: The focal length of the mirror is f and distance of the object from the focus is u, the magnification of the mirror is

\frac{f}{u}

.

Reason:

M a g n i f i c a t i o n = \frac{S i z e o f i m a g e}{S i z e o f o b j e c t}

HARD

Physics>Optics>Reflection of Light>Mirror Equation

The distance of an object from a spherical mirror is equal to the focal length of the mirror. Then the image :

What is linear magnification?

Important Questions on Reflection of Light

Learn and Prepare for any exam you want !