The formation of the oxide ion, O 2 - ( g ) , from oxygen atom requires first an exothermic and then an endothermic step as shown in below: O g + e - ⟶ O - g ; Δ f H ⊖ = - 141 k J m o l - 1 O - g + e - ⟶ O 2 - g ; Δ f H ⊖ = + 780 k J m o l - 1 Thus process of formation of O 2 - in gas phase is unfavourable though O 2 - is isoelectronic with neon. It is due to the fact that,

Electron repulsion outweighs the stability gained by achieving noble gas configuration.

O - Ion has comparatively smaller size than oxygen atom.

Oxygen is more electronegative.

Addition of electron in oxygen results in larger size of the ion.

E M B I B E

Alpha Question Bank for Medical: Chemistry>Chapter 13 - Chemical Bonding and Molecular Structure>Exercise 1>Q 2

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What is the hybridisation of positively charged nitrogen atom?

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Important Questions on Chemical Bonding and Molecular Structure

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Alpha Question Bank for Medical: Chemistry>Chapter 13 - Chemical Bonding and Molecular Structure>Exercise 1>Q 3

In which of the following molecules is the nitrogen atom

{sp}^{2}

hybridised?

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Alpha Question Bank for Medical: Chemistry>Chapter 13 - Chemical Bonding and Molecular Structure>Exercise 1>Q 4

What happens to

H - N - H

bond angle when

{NH}_{3}

reacts with

HCl

?

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Alpha Question Bank for Medical: Chemistry>Chapter 13 - Chemical Bonding and Molecular Structure>Exercise 1>Q 5

Which oxide of

N

is paramagnetic?

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Alpha Question Bank for Medical: Chemistry>Chapter 13 - Chemical Bonding and Molecular Structure>Exercise 1>Q 6

In beryllium chloride the hybridization possible in beryllium is:

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Alpha Question Bank for Medical: Chemistry>Chapter 13 - Chemical Bonding and Molecular Structure>Exercise 1>Q 7

Column A describe nature of bonding and Column B the solid having that type of bonding:

A Nature of bonding)		B (solid)
I	Van der Waals	P	$Al, Cd$
II	lonic	Q	${CO}_{2}, H_{2}$
III	Metallic	R	$Si$ , diamond
IV	Covalent	S	$MgO, NaCl$

Correct matching of A and B is in alternate:

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Alpha Question Bank for Medical: Chemistry>Chapter 13 - Chemical Bonding and Molecular Structure>Exercise 1>Q 8

Hybridization of orbitals of carbon in

{CH}_{4}

is necessary to explain which of the following:

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Alpha Question Bank for Medical: Chemistry>Chapter 13 - Chemical Bonding and Molecular Structure>Exercise 1>Q 9

In which of the following, '

N

' atom is

{sp}^{2}

hybridized:

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Alpha Question Bank for Medical: Chemistry>Chapter 13 - Chemical Bonding and Molecular Structure>Exercise 1>Q 10

The hybridization of carbon atoms in

C_{2} - C_{3}

single bond of

\overset{1 2 3 4}{HC \equiv C - CH = {CH}_{2}}

is:

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