Distinguish between half-wave and full-wave rectifiers.

Half-wave rectifier: (i) The rectified output is for only half of the ac cycle. (ii) One diode is used for rectification. (iii) Secondary of the transformer supplies the input across the two terminals of a diode along with a load. (iv) The output is taken across the load connected in series with the diode. Full-wave rectifier(centre-tapped rectifier): (i) The rectified output is for the complete ac cycle i.e. positive as well as the negative half. (ii) Two diodes are used and each rectifies in the alternate half cycle. (iii) The input by the secondary of a transformer is provided at the two terminals connected to the p - side of the two diodes. (iv) The output is taken between the centre tap of the transformer and the common terminal of the n - sides of two diodes.

What is rectification? Explain the working of a full wave rectifier.

The conversion of alternating current into the direct current is called rectification. Diodes are used for rectification because they allow the unidirectional flow of current. Diodes conduct only when they are forward biased. When two diodes are used in a circuit we get the output voltage during the positive and negative half cycles of the input ac voltage. The circuit for a full-wave rectifier is shown below: For a full-wave rectifier, the secondary of a transformer is provided with a centre-tapping. The p - side of two diodes is connected to the two ends of the secondary of a transformer. The n - side of the diodes are connected together and the output is taken between the common point of diodes and the midpoint of the secondary transformer. We know that a diode conducts when it is forward biased. When A is positive, the diode D 1 conducts and when B is positive then D 2 conducts. Each diode rectifies only for half of the cycle, but the two do it for alternate half cycles. Thus, the output between their common terminal and the centre-tap of the transformer becomes a full-wave rectifier output. The input and output signal of a full-wave rectifier is shown below.

E M B I B E

Physics Crash Course (Based on Revised Syllabus-2023)>Chapter 15 - Semiconductor Electronics: Materials, Devices and Simple Circuits>Exercise>Q 35

HARD

12th Andhra Pradesh Board

IMPORTANT

Earn 100

What is the main difference between a solar cell and a photodiode?

Important Questions on Semiconductor Electronics: Materials, Devices and Simple Circuits

EASY

12th Andhra Pradesh Board

IMPORTANT

Physics Crash Course (Based on Revised Syllabus-2023)>Chapter 15 - Semiconductor Electronics: Materials, Devices and Simple Circuits>Exercise>Q 36

What is Zener voltage $(V_{z})$ and how will a Zener diode be connected in circuits generally?

EASY

12th Andhra Pradesh Board

IMPORTANT

Physics Crash Course (Based on Revised Syllabus-2023)>Chapter 15 - Semiconductor Electronics: Materials, Devices and Simple Circuits>Exercise>Q 37

In which bias can a Zener diode be used as voltage regulator?

HARD

12th Andhra Pradesh Board

IMPORTANT

Physics Crash Course (Based on Revised Syllabus-2023)>Chapter 15 - Semiconductor Electronics: Materials, Devices and Simple Circuits>Exercise>Q 38

Distinguish between zener breakdown and avalanche breakdown.

HARD

12th Andhra Pradesh Board

IMPORTANT

Physics Crash Course (Based on Revised Syllabus-2023)>Chapter 15 - Semiconductor Electronics: Materials, Devices and Simple Circuits>Exercise>Q 39

What is a photodiode? Explain its working with a circuit diagram and draw its $I - V$ characteristics.

MEDIUM

12th Andhra Pradesh Board

IMPORTANT

Physics Crash Course (Based on Revised Syllabus-2023)>Chapter 15 - Semiconductor Electronics: Materials, Devices and Simple Circuits>Exercise>Q 40

Explain the working of LED and what are its advantages over conventional incandescent low power lamps.

HARD

12th Andhra Pradesh Board

IMPORTANT

Physics Crash Course (Based on Revised Syllabus-2023)>Chapter 15 - Semiconductor Electronics: Materials, Devices and Simple Circuits>Exercise>Q 41

Explain the working of a solar cell and draw its $I - V$ characteristics.

EASY

12th Andhra Pradesh Board

IMPORTANT

Physics Crash Course (Based on Revised Syllabus-2023)>Chapter 15 - Semiconductor Electronics: Materials, Devices and Simple Circuits>Exercise>Q 42

Calulate the current amplification factor $β$ (beta) when change in collector current is $1 mA$ and change in base current is $20 μA$ .

EASY

12th Andhra Pradesh Board

IMPORTANT

Physics Crash Course (Based on Revised Syllabus-2023)>Chapter 15 - Semiconductor Electronics: Materials, Devices and Simple Circuits>Exercise>Q 43

For a transistor amplifier, the collector load resistance $R_{L} = 2 kΩ$ and the input resistance $R_{i} = 1 kΩ$ . If the current gain is $50$ , calculate the voltage gain of the amplifier.

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