If the rate constant of a first order reaction is 6 . 93 × 10 - 4 per second, what is its half-life period ?

The half-life of a reaction is the time in which the concentration of a reactant is reduced to one half of its initial concentration. Given, rate constant of a first order reaction, k = 6 . 93 × 10 - 4 sec - 1 . Half-life period, t 1 / 2 = ? We know, half-life period of first order reaction, t 1 / 2 = 0 . 693 k Substituent the rate constant of a first order reaction in the above formula, t 1 / 2 = 0 . 693 6 . 93 × 10 - 4 = 1000 Hence, the half-life period of first order reaction, t 1 / 2 = 1000 seconds.

The rate constant of a first order reaction is, k = 7 . 39 × 10 - 5 sec - 1 . Find the half-life of the reaction.

The half-life of a reaction is the time in which the concentration of a reactant is reduced to one half of its initial concentration. Given, rate constant of a first order reaction, k = 7 . 39 × 10 - 5 sec - 1 . Half-life period, t 1 / 2 = ? We know, half-life period of first order reaction, t 1 / 2 = 0 . 693 k Substituent the rate constant of a first order reaction in the above formula, t 1 / 2 = 0 . 693 7 . 39 × 10 - 5 = 0 . 093 × 10 5 sec . Hence, the half-life period of first order reaction, t 1 / 2 = 0 . 093 × 10 5 seconds.