Write labelled chemical equations to show what happens when toluene reacts with chlorine in the presence of light followed by hydrolysis at 373 K

Reaction of methyl benzene i.e. toluene with chlorine in the presence of sunlight is a free radical substitution reaction. In this reaction hydrogen atoms from side chain get replaced by chlorine. On mono chlorination benzyl chloride is formed and on dichlorination, benzal chloride is formed and on tri chlorination, 1,2,4 trichlorobenzene is formed. The equation for the reaction is:

Complete the following equation and write the major product ' B ' C 6 H 5 Cl + Na → dry ether B

When chlorobenzene is heated with sodium metal in the presence of dry ether, the chlorine atom of chlorobenzene is replaced by the phenol group and diphenyl is obtained. This is called fitting reaction. The product formed is:

Complete the following equation and write the major product ' A ' . CH 3 - CH 2 - CH = CH 2 + HBr → A

The given equation follows anti-markownikoff's rule. This rule states that the hydrogen atom of HX becomes bonded to the carbon atom that had the least number of hydrogen atoms in the starting alkene or alkyne. Here, peroxide acts as a catalyst. So, the complete equation is: CH 3 - CH 2 - CH = CH 2 + HBr → peroxide CH 3 - CH 2 - CH 2 - CH 2 Br

Write chemical equation for the following conversion : Acetaldehyde to Butan-2-ol

Grignard reagents add to the carbonyl group of aldehyde and ketones forming an adduct which on acid hydrolysis produce alcohols. Ethyl magnesium bromide reacts with acetaldehyde to give butan-2-ol.

Complete the following reaction and write the names of the main product formed :

In the elimination reaction a haloalkane reacts with alcoholic solution of potassium hydroxide and forms an alkene. In this reaction a halogen atom is eliminated from the α -carbon and a hydrogen is eliminated from the β -carbon of the haloalkane so that an alkene is formed. In the case of haloalkanes which has more than one β -position, can eliminate the hydrogen halide in 2 different ways, then that alkene will be preferred in which carbon atoms joined by the double bond are maximally alkylated. Thus, 2-chlorobutane on reaction with alcoholic solution of KOH gives 2-butene as major product.

Complete the following reaction and write the name of the main product formed :

Haloarenes undergo the usual electrophilic substitution reactions of the benzene ring. In chlorobenzene the electron density increases at Ortho and para positions because of resonance. However, because of steric hindrance, at the ortho position, the para product usually predominates over ortho product. Chloro benzene reacts with acetyl chloride in the presence of anhydrous aluminium chloride to give o -chloroacetophenone and p -chloroacetophenone. Major product formed in this reaction is p -chloroacetophenone.

Complete the following reactions and write the names of the main product formed : CH 3 CH 2 CH 2 Cl → AgCN ?

Haloalkanes react with silver cyanide to give isocyanide along with small amount of cyanoalkanes. Propyl chloride reacts with silver cyanide to form propyl cyanide and silver chloride. The major product formed in this reaction is butyronitrile. CH 3 CH 2 CH 2 Cl → AgCN CH 3 CH 2 CH 2 CN + AgCl

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EMBIBE CHAPTER WISE PREVIOUS YEAR PAPERS FOR CHEMISTRY>Chapter 10 - Haloalkanes and Haloarenes>Goa Board-2018>Q 1

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When 2-chlorobutane reacts with hot alcoholic $KOH$ , the major product formed is

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Chapter-Wise 3D Chemistry Videos from Embibe Experts EMBIBE CHAPTER WISE PREVIOUS YEAR PAPERS FOR CHEMISTRY

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