When npn transistor is used as an amplifier

In the circuit shown, the value of $\beta$ of the transistor is $48$. If the supplied base current is $200 \mathrm{\mu A}$, what is the voltage at the terminal $Y$?

The typical output characteristics curve for a transistor working in the common-emitter configuration is shown in the figure.

The estimated current gain from the figure is

Match the following List-I with List-II

The correct answer is:

If $\alpha =0.99$ for a CE transistor amplifier circuit. The input resistance is equal to $1 \mathrm{k\Omega }$ and the load resistance is equal to$100 \mathrm{k\Omega }$  to , the voltage gain of the circuit is 

:

In a common emitter amplifier, the input resistance and output resistance are $200\mathrm{\Omega }$ and $500\mathrm{\Omega }$ respectively. If the voltage gain of the amplifier is $50$, then the power gain is

For a given transistor amplifier circuit in CE configuration $V_{CC}=1 \mathrm{V},R_C=1 \mathrm{k\Omega },R_b=100 \mathrm{k\Omega }$ and $\beta =100$. Value of base current $I_b$is

In $\mathrm{CE}$ $\mathrm{NPN}$ transistor ${10}^{10}$ electrons enter the emitter in ${10}^{-6} \mathrm{s}$ when it is connected to the battery. About $5\%$ electrons recombine with holes in the base. The current gain of the transistor is __________

$\left(e=1.6\times {10}^{-19}\mathrm{C}\right)$