Area of a General Quadrilateral

Find the area of the quadrilateral based on the given measurements in the following figure:

The area of Neelima's quadrilateral plot is 80 square meters. If one of its diagonals has a length of 16 meters, find the length of the other diagonal.

In the figure, the area of quadrilateral ABCD is 24 square centimeters, and OD = 3 cm

Find the length of diagonal AC

In the figure, the area of quadrilateral ABCD is 24 square centimeters, and OD = 3 cm.

Find the length of diagonal BD.

The Diagonal $AC=15 cm$ of $ABCD$ and the lengths of the perpendiculars drawn from $B$ and $D$ to $AC$ are $3 cm$ and $5 cm$ respectively. Then find the area of the quadrilateral $ABCD$. 

The area of a rhombus is $2016 {\mathrm{cm}}^2$ and its sides are $65 \mathrm{cm}$ each. Find the lengths of its diagonals.

The perimeter of a rhombus is $100 \mathrm{cm}$. If one of the diagonal be $40 \mathrm{cm}$, then the other diagonal is _____ $\mathrm{cm}$.

The diagonals of a rhombus are $12 \mathrm{cm}$ and $15 \mathrm{cm}$. The area of the rhombus is equal to

If the area of the parallelogram with base $=60 \mathrm{cm}$ and height $=30 \mathrm{cm}$ is $\mathrm{k} {\mathrm{cm}}^2$, then find $\mathrm{k}$.

If the diagonal $d$ of a quadrilateral is doubled and the heights $h_1$ and $h_2$ falling on $d$ are halved, then the area of quadrilateral _____.

The area of a rhombus whose diagonals are $10 \mathrm{cm}$ and $20 \mathrm{cm}$ is equal to
 

An auditorium hall is in the shape of a rhombus such that the lengths of the two diagonals of the hall are $12 \mathrm{m}$ and $16 \mathrm{m}$. Find the cost of painting the floor at the rate of $₹ 6.50 \mathrm{per} \mathrm{sq}. \mathrm{m}$.

The length of a diagonal of a quadrilateral shaped field is $48 \mathrm{m}$ and the lengths of perpendiculars dropped on it from the remaining opposite vertices are $16 \mathrm{m}$ and $26 \mathrm{m}$. Find the area of the field.

If the lengths of two diagonals of a rhombus are $16 \mathrm{cm}$ and $30 \mathrm{cm}$, find the area and the length of the side of the rhombus.

The area of rhombus is $120 {\mathrm{cm}}^2$ and one of the diagonal is $24 \mathrm{cm}$. Each side of rhombus is:

Each side of a rhombus is $15 \mathrm{cm}$ and the length of one of its diagonal is $24 \mathrm{cm}$. The area of the rhombus is:

The diagonal of a quadrilateral is $20 \mathrm{cm}$ in length and the lengths of perpendiculars on it from the opposite vertices are $8.5 \mathrm{cm}$ and $11.5 \mathrm{cm}$.The area of quadrilateral is:

Find the area of a quadrilateral one of whose diagonals is $40 \mathrm{cm}$ and the lengths of the perpendiculars drawn from the opposite vertices on the diagonal are $16 \mathrm{cm}$ and $12 \mathrm{cm}$.

The perimeter of a rhombus is $180 \mathrm{cm}$ and one of its diagonals is $72 \mathrm{cm}$. Find the length of the other diagonal and the area of the rhombus.

To tile the floor of a room of dimensions $8 \mathrm{m} \times 4·8 \mathrm{m},$ rhombus-shaped tiles of diagonals $16 \mathrm{cm}$ and $12 \mathrm{cm}$ costing $₹24$ and square-shaped tiles of diagonal $16 \mathrm{cm}$ costing $₹28$ are available. Which type of tiles should be chosen to minimize the cost? How much can be saved by choosing the right type over the other?