Equipotential Surfaces

In the electric field of charge $Q,$ another charge is carried from $A$ to $B$, $A$ to $C,$ $A$ to $D$ and $A$ to $E,$ then work done will be -

Assertion: The surface of a conductor is an equipotential surface.

Reason: Conductor allows the flow of charge.

Assertion : At a point in space, the electric field points towards north. In the region, surrounding this point the rate of change of potential will be zero along the east and west.

Reason : Rate of change of electric potential is along the direction of electric field.

What is the angle between the electric field and the plane of an equipotential surface?

Electric field in a region is increasing in magnitude along $x$-direction. The equipotential surfaces associated are

Figure shows some equipotential lines distributed in space. A charged particle is moved from point $\mathrm{A}$ to point $\mathrm{B}$

The figure shows two parallel equipotential surfaces A and B kept a small distance r apart from each other. A point charge of q coulomb is taken from the surface A to B. The amount of net work done will be :-

In moving from $A$ to $B$ along an electric field line, the electric field does $6.4\times {10}^{-19} \mathrm{J}$ of work on a electron. If ${\varphi }_1, {\varphi }_2$ are equipotential surfaces, then the potential difference $\left(V_C-V_A\right)$ is :

A hollow conducting sphere is placed in an electric field produced by a point charge placed at $P$ as shown in figure. Let $V_A, V_B, V_C$ be the potential at points $A, B$ and $C$ respectively. Then:

A hollow conducting sphere is placed in an electric field produced by a point charge placed at $P$ as shown in figure. Let $V_{\mathrm{A}},V_B,V_C$ be the potentials at points $A, B$ and $C$ respectively. Then

Some equipotential surfaces, which are normal to $x$-$y$ plane are shown in the adjoining figure the direction of the electric field is:

(A) 

(B) 

(C) 

(D) 

Assertion:- Electrostatic field lines are perpendicular to the surface of conductor.

Reason:- Surfaces of a conductor are equipotential.

Assertion: For a conductor, when observed at very large distance, equipotential surfaces are plane. 

Reason: Electrostatic field is a conservative field.

Assertion: Electric lines of force are normal to any equipotential surface at all points on the surface.

Reason: Electric field is strong at points where equipotential surfaces are crowded and vice-versa.

Figure shows a family of parallel equipotential surfaces and four paths along which an electron is made to move from one surface to another as shown.

(A) What is the direction of the electric field?

(B) Rank the paths according to work done, greatest first.

The diagrams below show regions of equipotentials:

       (a)                   (b)                       (c)                  (d)

A positive charge is moved from A to B in each diagram.

In the electric field of charge $Q$, another charge is carried from $A$ to $B$, $A$ to $C,A$ to $D$ and $A$ to $E$, then work done will be:

A circle of radius $R$ is drawn in a uniform electric field $E$ as shown in the fig. $V_A,V_B,V_c$ are respectively the potentials of points $A,B,C$ and $D$ on the circle then:

In the presence of an electric field due to charge $q$ at the centre, a point charge is carried from $\mathrm{A}$ to $\mathrm{B}$, $\mathrm{C}$, $\mathrm{D}$ & $\mathrm{E}$. Then, out of the following option, which is correct about the work done.

In an  equipotential region