Force on a Current Carrying Conductor in Magnetic Field

A semi circular current carrying wire having radius $R$ is placed in $\mathrm{x}-\mathrm{y}$ plane with its centre at origin $\mathrm{{\rm O}}$. There is non-uniform magnetic field $\overrightarrow{B}=\left(\frac{{\mathrm{B}}_{\mathrm{o}}\mathrm{x}}{\mathrm{2}\mathrm{R}}\right)\widehat{\mathrm{k}}$ $\left(\text{here}{B}_{\mathrm{o}} \text{is} +\text{ve constant}\right)$  is existing in the region. The magnetic force acting on semi-circular wire will be along:

Electric charge $q$ is uniformly distributed over a rod of length $l$. The rod is placed parallel to a long wire carrying a current $i$. The separation between the rod and the wire is $a$. Find the force needed to move the rod along its length with a uniform velocity $v$.

Figure shows a rectangular current-carrying loop placed $2 cm$ away from a long, straight, current-carrying conductor. What is the magnitude of the net force acting on the loop in ${10}^{-4}N$.

A current carrying wire is placed parallel to the lines of force in a magnetic field.

The horizontal component of Earth’s magnetic field at a certain place is $3.0\times {10}^{-5}\mathrm{ }\mathrm{T}$. It is directed from the geographic south to the geographic north. The force per unit length on a very long straight conductor carrying a steady current of $1.2\mathrm{ }\mathrm{A}$ in east-west direction is:

A current of $10 \mathrm{A}$ is flowing in a wire of length $1.5 \mathrm{m}$. A force of $15 \mathrm{N}$ acts on it when it is placed in a uniform magnetic field of $2 \mathrm{T}$. The angle between the magnetic field and the direction of the current is:

A metal wire of mass $m$ slides without friction on two rails placed at a distance $l$ apart. The track lies in a uniform vertical magnetic field$B$. A constant current $i$ flows along the rails across the wire and back down the other rail. The acceleration of the wire is

$3 \mathrm{A}$ of current is flowing in a linear conductor having a length of $40 \mathrm{cm}$. The conductor is placed in a magnetic field of strength $500 \mathrm{gauss}$ and makes an angle of $30°$ with direction of the field. It experiences a force of magnitude

Two free parallel wires carrying currents in the opposite directions

A horizontal wire of length $0.05 \mathrm{m}$ carries a current of $5 \mathrm{A}$. If the mass of the wire is $10 \mathrm{milligrams}$, the minimum magnetic field required to support the weight of the wire is $\left(\mathrm{g}=10 \mathrm{m} {\mathrm{s}}^{-2}\right)$

Cotyledons are also called-

The magnetic force per unit length on a wire carrying a current of $10\mathrm{ }\mathrm{A}$ and making an angle of $45°$ with the direction of a uniform magnetic field of $0.20\mathrm{ }\mathrm{T}$ is

The horizontal component of Earth’s magnetic field at a certain place is $3.0\times {10}^{-5}\mathrm{ }\mathrm{T}$. It is directed from the geographic south to the geographic north. The force per unit length on a very long straight conductor carrying a steady current of $1.2\mathrm{ }\mathrm{A}$ in east-west direction is:

A current of $10 \mathrm{A}$ is flowing in a wire of length $1.5 \mathrm{m}$. A force of $15 \mathrm{N}$ acts on it when it is placed in a uniform magnetic field of $2 \mathrm{T}$. The angle between the magnetic field and the direction of the current is:

A loop of flexible conducting wire lies in a magnetic field of $2.0 \mathrm{T}$with its $P$ perpendicular to the field. The length of the wire is $1 \mathrm{m}$. When a current of $1.1 \mathrm{A}$ is passed through the loop. It opens into circle, then the tension developed in the wire is

A conducting circular loop of radius $r$ carries a constant current $i$ . It is placed in a uniform magnetic field $B$, such that $B$ is perpendicular to the plane of the loop. The magnetic force acting on the loop is

A conductor $\mathrm{AB}$ of length $l$ carrying a current $i$ is placed perpendicular to a long straight conductor $\mathrm{XY}$ carrying a current $I$ as shown. The force on $\mathrm{AB}$ will be

Currents of 10 A , 2 A are passed through two parallel wires A and B respectively in opposite directions. If the wire A is infinetely long and the length of the wire B is 2 metre, the force on the conductor B, which is situated at 10cm distance from A will be

A horizontal wire of length 0.05m carries a current of 5A. If the mass of the wire is 10mg, the minimum magnetic field required to support the weight of the wire is $\left(\mathrm{g}=10\frac{\mathrm{m}}{{\mathrm{s}}^2}\right)$