Formation of Standing Waves in an Air Column

The ratio of first harmonic of open organ pipe and closed organ pipe for the same length is

fundamental frequency of closed organ pipe is ( $\mathrm{V}=$velocity of sound in air, $\mathrm{L}=$Length of organ pipe)

Fundamental frequency of open organ pipe is ( $\mathrm{V}=$Velocity of sound in air, $\mathrm{L}=$Length of pipe)

For a organ pipe of length $L$, closed at both ends, the first displacement node is presend at :

A pipe open at both ends has a fundamental frequency $f$ in air. The pipe is dipped vertically in water so that half of it is in water. The fundamental frequency of the air column is now:

A source of frequency 340 Hz is kept above a vertical cylindrical tube closed at lower end. The length of the is 120cm. Water is slowly poured in just enough to produce resonance. Then the minimum height (velocity of sound = $340m/s$ ) of the water level in the tube for that resonance is,

The fundamental frequency of an air column in a pipe closed at one end is $100 \mathrm{Hz}$. If the same pipe is open at both the ends, the frequencies produced in $\mathrm{Hz}$ are

The frequency of the first overtone of a closed pipe of length $l_c$ is equal to that of the third overtone of an open pipe of length $l_o$. The ratio $\frac{l_o}{l_c}$ will be,

In case of a closed organ pipe which harmonic, the $p^{\mathrm{th}}$ overtone will be?

A pipe closed at one end has length $83 \mathrm{cm}$. The number of possible natural oscillations of air column whose frequencies lie below $1000 \mathrm{Hz}$ are (velocity of sound in air $=332 \mathrm{m} {\mathrm{s}}^{-1}$)

An open organ pipe has a fundamental frequency $100 \mathrm{Hz}$. What frequency will be produced if its one end is closed?

A pipe $30 \mathrm{c}\mathrm{m}$long, is open at both ends. Which harmonic mode of the pipe resonates a $1.1 \mathrm{k}\mathrm{H}\mathrm{z}$ source?
(Speed of sound in air$=330 \mathrm{m}\mathrm{ }{\mathrm{s}}^{-1}$)

As an empty vessel is filled with water, its frequency:

An open pipe of length $33 \mathrm{cm}$ resonates with frequency of $1000 \mathrm{Hz}$ . If the speed of sound is $330\mathrm{m}/\mathrm{s}$, then this frequency is:

An organ pipe  ${\mathrm{P}}_1$ closed at one end vibrating in its first overtone and another pipe ${\mathrm{P}}_2$ open at both ends vibrating in its third overtone are in resonance with a given tuning fork. The ratio of the length of ${\mathrm{P}}_1$ to that of${\mathrm{P}}_2$ is:

A closed organ pipe of length $\mathrm{L}$ and an open organ pipe contain gases of densities${\mathrm{\rho }}_1 \mathrm{and} {\mathrm{\rho }}_2$ respectively. The compressibility of gases is same in both the pipes which are vibrating in their first overtone with same frequency. The length of the open organ pipe is:

Tube $A$ has both ends open while tube $B$ has one end closed. Otherwise, they are identical. The ratio of fundamental frequency of tube $A$ and $B$ is,

A resonance pipe is open at both ends and $30 \mathrm{cm}$ of its length is in resonance with an external frequency $1.1 \mathrm{kHz}$. If the speed of sound is $330 \mathrm{m} {\mathrm{s}}^{-1}$, which harmonic is in resonance?

The second overtone of an open pipe is in resonance with the first overtone of a closed pipe of length 2m. length of the open pipe is

A closed pipe is suddenly opened and changed to an open pipe of same length. The fundamental frequency of the resulting open pipe is less than that of $3^{rd}$ harmonic of the earlier closed pipe by $55 \mathrm{Hz}$. Then, the value of fundamental frequency of the closed pipe is