AC Voltage Applied to a Inductor

An inductor of inductance $2 \mathrm{mH}$ is connected to a $220 \mathrm{V}, 50 \mathrm{Hz}$ a.c. source. Let inductive reactance in the circuit is $X_1$. If a $220 \mathrm{V}$ d.c. source replaces the a.c. source in the circuit, then the inductive reactance in the circuit is $X_2$. $X_1$ and $X_2$ respectively are

An inductor of inductance $2 \mathrm{mH}$is connected to a $220 \mathrm{V}, 50 \mathrm{Hz}$ a.c. source. Let the inductive reactance in the circuit be ${\mathrm{X}}_1$. If a$220 \mathrm{V}$ dc source replaces the ac source in the circuit, then the inductive reactance in the circuit is$X_2$. $X_1 \mathrm{and} X_2$, respectively are:

As per the given graph, choose the correct representation for curve $A$ and curve $B$
{Where $X_C=$ Reactance of pure capacitive circuit connected with A.C. source
$X_L=$ Reactance of pure inductive circuit connected with A.C. source
$R=$ Impedance of pure resistive circuit connected with A.C. source
$Z=$ Impedance of the $LCR$ series circuit }

The variation of impedance $\left(Z\right)$ with angular frequency $\left(\omega \right)$ for two electrical elements is shown in the graph given.

If $X_L, X_C$ and $R$ are inductive reactance, capacitive reactance and resistance respectively, then

A coil of inductance $0.1 \mathrm{H}$ and resistance $110 \mathrm{\Omega }$ is connected to a source of $110 \mathrm{V}$ and $350 \mathrm{Hz}$. The phase difference between the voltage maximum and the current maximum is

Statement 1: An ac circuit can be created with zero reactance.

Statement 2: An ac circuit without power is not possible.

In the circuit shown, a $30 \mathrm{V}$ d.c. source gives a current $2.0 \mathrm{A}$ as recorded in the ammeter $\mathrm{A}$ and $30 \mathrm{V}$ a.c. source of frequency) $100 \mathrm{Hz}$ gives a current $1.2\mathrm{A}$. The inductive reactance is

In the circuit shown in the figure the inductance of coil is $\mathrm{L}=10\mathrm{mH}$ and capacitance of the capacitor is $C=0.2\mathrm{mF}$. The circuit is powered by an A.C. voltage source. If value of current measured by ammeter does not depend on resistor, then frequency of source is:

If the current in inductance is $0.8 \mathrm{A}$ and that in capacitance is $0.6 \mathrm{A}$. What is the current drawn from the source?

The average power dissipated in a pure inductance is

The graph between inductive reactance and frequency is 

Peak value fo a.c in purely inductive circuit is

When ac voltage applied to circuit containing inductor only lagging of current with voltage by

The average power dissipated in a pure inductor is

The reactance of an inductor at $50 \mathrm{Hz}$ is $10 \mathrm{\Omega }.$ The reactance of it at $200 \mathrm{Hz}$ is:

A choke is preferred to a resistance for limiting current in ac circuit because:

A series $LR$ circuit is connected to a voltage source with $V\left(t\right)=V_0\sin \left(\omega t\right)$ . After a very large time, current $I\left(t\right)$ behaves as $\left(t_0\gg \frac{L}{R}\right)$:

A resistance of $300\mathrm{\Omega }$ and an inductance of $\frac{1}{\mathrm{\pi }}$ henry are connected in series to an ac voltage of $20$ volts and $200 \mathrm{Hz}$ frequency. The phase angle between the voltage and current is :-

A voltage ${\mathrm{V}}_{\mathrm{PQ}}={\mathrm{V}}_0\cos \left(\mathrm{\omega t}\right)$ (where, ${\mathrm{V}}_0$ is a real amplitude) is applied between the points $\mathrm{P}$ and $\mathrm{Q}$ in the network shown in the figure. The values of capacitance and inductance are $\mathrm{C}=\frac{1}{\text{ω}\mathrm{R}\sqrt{3}}$ and $\mathrm{L}=\frac{\mathrm{R}\sqrt{3}}{\mathrm{\omega }}$. Then, the total impedance between $\mathrm{P}$ and $\mathrm{Q}$ is

A coil of inductance $5.0 \mathrm{mH}$ and negligible resistance is connected to an alternating voltage $V=10\sin \left(100t\right) \mathrm{V}\text{.}$ The peak current in the circuit will be :